• Continues Numbers & Alike Numbers

    1... COUPLES OF CONTINUES NUMBERS
    For every two couples of continues numbers, holds that: if the SECOND number from the first couple of numbers is added to the FIRST number from the second couple of numbers, if we then subtract from the result of the addition the FIRST number from the first couple of numbers then the result will be the SECOND number of the second couple of numbers, e.g.

    First Couple of Numbers
    Second Couple of Numbers
    1
    101
    2
    102

    We add the SECOND number from the first couple of numbers to the FIRST number from the second couple of numbers (2 + 101 = 103). From the result of the addition we subtract the FIRST number from the first couple of numbers (103 - 1 = 102). The result is the SECOND number from the second couple of numbers (102).

    Proof:

    If we assign variables to the numbers we take:

    1 = α, 2 = β, 101 = γ, 102 = δ

    We now use these variables in order to construct a general equation which will be capable of describing the general case of the example given above.

    We take:

    (β + γ) - α = δ

    Observing that: α = β - 1 and δ = γ + 1

    We introduce into the equation the corresponding equivalents of the variables α and δ.

    We take:

    (β + γ) - (β - 1) = γ + 1

    We solve the equation in respect to the first part in order to obtain the second:

    (β + γ) - (β -1) = β + γ - β + 1 = β + γ - β + 1 = γ + 1



    2... SERIES ADDITIONS BETWEEN ALIKE NUMBERS

    6 + 6 = 12

    66 + 66 = 132

    666 + 666 = 1332

    6666 + 6666 = 13332

    66666 + 66666 = 133332

    [6 * n] + [6 * n] = 1[3 * n-1]2

    7 + 7 = 14

    77 + 77 = 154

    777 + 777 = 1554

    7777 + 7777 = 15554

    77777 + 77777 = 155554

    [7 * n] + [7 * n] = 1[5 * n-1]4

    8 + 8 = 16

    88 + 88 = 176

    888 + 888 = 1776

    8888 + 8888 = 17776

    88888 + 88888 = 177776

    [8 * n] + [8 * n] = 1[7 * n-1]6

    9 + 9 = 18

    99 + 99 = 198

    999 + 999 = 1998

    9999 + 9999 = 19998

    99999 + 99999 = 199998

    [9 * n] + [9 * n] = 1[9 * n-1]8

    9 + Two Digit Number

    9 + 10 = 19

    9 + 11 (1 + 1 = 2) = 20 (2 + 0 = 2)

    9 + 12 (1 + 2 = 3) = 21 (2 + 1 = 3)

    9 + 13 (1 + 3 = 4) = 22 (2 + 2 = 4)

    9 + 14 (1 + 4 = 5) = 23 (2 + 3 = 5)

    9 + 94 (9 + 4 = 13 (1 + 3 = 4)) = 103 (1 + 0 + 3 = 4)

    9 + Three Digit Number

    9 + 111 (1 + 1 + 1 = 3) = 120 (1 + 2 + 0 = 3)

    9 + 458 (4 + 5 + 8 = 17) = 467 (4 + 6 + 7 = 17)

    9 + Four Digit Number

    9 + 5478 (5 + 4 + 7 + 8 = 24) = 5487 (5 + 4 + 8 + 7 = 24)